WAEC GCE 2023 MATHEMATICS ESSAY AND OBJ ANSWERS

WAEC GCE 2023 MATHEMATICS ESSAY AND OBJ ANSWERS – EXAMGRAND.COM.NG
••••••••••••••••••••••••••••••••••••••••••••••••••••MAKE SURE YOU KEEP REFRESHING FOR NEW ANSWERS!!!!!✊
CLICK HERE TO JOIN OUR TELEGRAM CHANNEL FOR ALL 2023 EXAM ANSWERS FOR FREE
••••••••••••••••••••••••••••••••••••••••••••••••••••
MATHEMATICS-OBJ

01-10: BABACDBBDA
11-20: CBABCCBCCA
21-30: DADACABADC
31-40: CCACBDCDCB
41-50: DACBAAACAC

Completed.


••••••••••••••••••••••••••••••••••••••••••••••••••••
MATHEMATICS -ESSAY- ANSWERS

NUMBER 1

To calculate the time it will take to reach the estimated amount of 1,049,740.00, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

where:
A is the final amount, P is the initial principal, r is the interest rate as a decimal, n is the number of times the interest is compounded in a year, and t is the number of years.

In this case, the initial principal is 400,000.00, the interest rate is 10% per annum (0.10 as a decimal), and the number of times the interest is compounded in a year is 1. The number of years, t, will be unknown.

Substituting these values into the formula, we can solve for t:

1,049,740.00 = 400,000.00(1 + 0.10/1)^(1t)

Using logarithms, we can simplify the equation:

log(1,049,740.00/400,000.00) = log(1 + 0.10/1)^(1t)

t = log(1,049,740.00/400,000.00) / log(1 + 0.10/1)

t = approximately 5.97 years

So it will take approximately 5 years and 11 months to reach the estimated amount of 1,049,740.00 if the village chief adds 100,000.00 to the amount at the end of each year.

(4a)
m = (y2 – y1) / (x2 – x1)
m = (5 – n) / (n + 2) = 4/3
(5 – n) / (n + 2) = 4/3
3(5 – n) = 4(n + 2)
15 – 3n = 4n + 8
7n = 7
n = 1

(4b)
sin x = 15/17
cos x = 8/17
5 sin x – 6 cos x = 5 (15/17) – 6 (8/17)
5 sin x – 6 cos x = 75/17 – 48/17
= 27/17

See also  WAEC EXTEND REGISTRATION FOR 2023 WASSCE & FINAL REGISTRATION DEADLINE


(5a)
Range = 145 – 110
= 35 cm.

(5b)
Q1 = 125
Q3 = 140
IQR = Q3 – Q1
= 140 – 125
= 15 cm

(5c)
mean = (110 + 120 + 120 + 125 + 128 + 130 + 135 + 140 + 142 + 145) / 10
= 1370 / 10
= 137 cm

No 6
No 7a

(9a)
V = πr^2h
r = d/2 = 3.5/2 = 1.75m
V_tanker = 6,500 * 0.001 = 6.5 m^3
V_total = 3 * 6.5 = 19.5 m^3

Substituting the values into the formula for the capacity of a cylindrical tank:

V = πr^2h
19.5 = π * (1.75)^2 * h
h = 19.5 / (π * (1.75)^2)

Using π = 22/7:
h = 19.5 / ((22/7) * (1.75)^2)
h = 0.37 m

(9b)
y – y1 = m(x – x1)
m = (y2 – y1) / (x2 – x1)
(x1, y1) = (2, -5) and (x2, y2) = (-4, -6)
m = (-6 – (-5)) / (-4 – 2) = -1

Recall;
y – y1 = m(x – x1)
y – (-5) = -1 (x – 2)
y + 5 = -1x + 2
y = -x + 7

No 10a

IMAGE FORM👇👇👇


Answers loading….

QUESTIONS👇


••••••••••••••••••••••••••••••••••••••••••••••••••••
••••••••••••••••••••••••••••••••••••••••••••••••••••
CLICK HERE TO JOIN OUR TELEGRAM CHANNEL FOR ALL 2023 EXAM ANSWERS FOR FREE
••••••••••••••••••••••••••••••••••••••••••••••••••••
Completed!!!
KEEP SHARING
……….

••••••••••••••••••••••••••••••••••••••••••••••••••

Be the first to comment

Leave a Reply

Your email address will not be published.


*